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Help needed on the general term of the following geometric series

I know that the general term of this geometric series is $r(1-r)$.
Here $r$ is the end term (i.e, the first term) and $1-r$ is the corresponding common ratio.
I would appreciate if someone would help me see how these steps work and correct my general understanding of a geometric series?
A geometric series is:
$$\sum_{k=1}^{\infty} A_k,$$
where $A_k = a^k$ (or $1/a$) and $\sum_{k=1}^{\infty}$ means that it is an infinite series.
My attempt:
I know that $r(1-r) = r – r^2$, and $r$ is the first term. But I don’t quite understand how to extrapolate from this into my next question.
If the general term of a geometric series is $r(1-r)$, then $A_k = r^{k} = (1 – r)^k$.
How can I further develop from here into my next question? If the goal is to find the sum of this geometric series, then what is the “next question”?
For example, would this be correct?
$$\sum_{k=1}^{\infty} (1 – r)^k = \
a2fa7ad3d0

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